> > There must be a subtlety I'm missing, right?What if the types are not instances of Eq? Jason
Thanks, I figured it was something simple. Now I just to convince myself there's no way around that. Is there a proof around somewhere? -- Chad Scherrer "Time flies like an arrow; fruit flies like a banana" -- Groucho Marx _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
