Stefan O'Rear <[EMAIL PROTECTED]> wrote: > The only type that you are allowed to assume corresponds to a C int is > CInt, in the Foreign.C.Types module. This probably isn't the problem, > but it could make problems of its own on a 64-bit or otherwise weird > system.
So say I turn everything back to pointers to CInt, what is the accepted way to convert from CInt to Int and CInt to Char? Is relying on the fact that CInt always wraps a Haskell integer an okay way to go? I might was well learn these things now, before I get into bad habits. -- _jsn _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
