Jason Dusek wrote:
Stefan O'Rear <[EMAIL PROTECTED]> wrote:
The only type that you are allowed to assume corresponds to a C int is
CInt, in the Foreign.C.Types module. This probably isn't the problem,
but it could make problems of its own on a 64-bit or otherwise weird
system.
So say I turn everything back to pointers to CInt, what is the
accepted way to convert from CInt to Int and CInt to Char?
Type class methods:
-- for numbers like Int, CInt
fromIntegral :: (Num b, Integral a) => a -> b
-- for Char
fromEnum :: (Enum a) => a -> Int
toEnum :: (Enum a) => Int -> a
> Is
relying on the fact that CInt always wraps a Haskell integer
an okay way to go?
I don't know what you mean by this.
> I might was well learn these things now,
before I get into bad habits.
Hope this helps,
Claude
--
http://claudiusmaximus.goto10.org
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