You'd have to write a wrapper that implements an array of triples
as a triple of arrays. This isn't too hard.

There's a new library in the works that should make this a lot easier

-- Don

abhay.parvate:
>    As far as I know, you can't. It needs machine representable types, such as
>    Int, Double, Char, etc. But making a tuple of three UArray Int Double may
>    help.
> 
>    2008/5/16 Lauri Oksanen <[EMAIL PROTECTED]>:
> 
>      Thanks for help. I did some tests with UArray and it does the trick.
>      The problem remaining is, how to implement UArray Int (Double, Double,
>      Double)?
>      UArray source code is far too cryptic for me.
> 
>      Regards,
>      Lauri
> 
>      On Fri, May 16, 2008 at 11:37 AM, Bulat Ziganshin
>      <[EMAIL PROTECTED]> wrote:
> 
>        Hello Lauri,
> 
>        Friday, May 16, 2008, 12:19:29 PM, you wrote:
> 
>        >      pixelArray :: Array Int Color
> 
>        it's boxed array which means that its elements are stored as thunks
>        computed only when you actually use them. try UArray instead:
> 
>        [3]http://haskell.org/haskellwiki/Modern_array_libraries
> 
>        --
>        Best regards,
>         Bulat                            mailto:[EMAIL PROTECTED]
> 
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