Aaron Tomb <[email protected]> writes: > As others have explained, the == operator doesn't tell you whether two > values are actually stored at the same location in memory.
Nobody yet mentioned that (==) doesn't guarantee *anything* - it's a user defined function. So while it may and should give structural equality, it also may not. -k -- If I haven't seen further, it is by standing in the footprints of giants _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
