While the discussion centers around overload resolution
let me re-iterate a point that (e.g.,) Java does nicely:

for their "x.f", if x :: T, then  you write  .f  (unqualified)
instead of  .T.f (qualified), even if you needed qualification
to declare the type of x, as in "foo.bar.T x;"

This requires a mixture of type checking (for x)
and name resolution (for f), which probably wouldn't fit
with Haskell's current module and type system. Too bad ...

Best - Johannes.

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