>ShowFloat -> Floating -> String I do not really understand this type.
Did you mean something like this: showFloat :: (Show a, Floating a) => a -> String showFloat = show In that case it depends on what type you fill in for 'a' and more specifically that type's Show instance. One value for which most (or all) show functions will give an error is ⊥ (undefined). If the type you pick is some kind of IEEE 754 type then you might have some trouble with denormalized values. But that is just a guess, you would have to test for that. If that is not what you mean than I would appreciate some clarification. Regards, Roel _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
