Hello, some details regarding my question. I got this assignment which gives me the following: SomeFunction :: Integer -> String. Which uses the show function to convert the Integer to String.
However it asks me how my function can fail? Well I know my function fails by definition when I do not insert an Integer into SomeFunction. Like SomeFunction 2.3425221 and now I also know that when I insert a number that is very close to zero (I think a denormalized value means that a value is very close to zero: http://www.haskell.org/pipermail/libraries/2004-November/002661.html) I get probably get an error. But that is normal as a 0.000001 * e^(-10) is not really an Integer, right? Now I also know that when I use 'undefined' I would get an error. So what other cases are there? (I asked my question about Floating because I guessed it would be similiar to Integers) At this moment I really can't figure out how my function can fail other than the inputs described above. Thanks for your help! 2009/11/27 Tsunkiet Man <[email protected]> > Hello, > > yes that is exactly what I mean, however I mean what kind of value do I > need to input in 'a' that gets me an error back? That is is from the > Floating class? (Other than undefined) > > Could you please explain to me what IEEE 754 is and what exactly is a > denormalized value? (After responding, I will google it also though). > > Thank you for your help, > > J.T.K.M. > > 2009/11/27 Roel van Dijk <[email protected]> > > >ShowFloat -> Floating -> String >> I do not really understand this type. >> >> Did you mean something like this: >> >> showFloat :: (Show a, Floating a) => a -> String >> showFloat = show >> >> In that case it depends on what type you fill in for 'a' and more >> specifically that type's Show instance. One value for which most (or >> all) show functions will give an error is ⊥ (undefined). If the type >> you pick is some kind of IEEE 754 type then you might have some >> trouble with denormalized values. But that is just a guess, you would >> have to test for that. >> >> If that is not what you mean than I would appreciate some clarification. >> >> Regards, >> Roel >> > >
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