See the http://hackage.haskell.org/package/split package. You should be able to do this by splitting the string on comma, and then splitting the result on 0, plus some plumbing.
Luke On Mon, Feb 21, 2011 at 11:46 PM, z_axis <[email protected]> wrote: > > I want to split "2,15,33,0,8,1,16,18" to ([2,15,33],[8,1,16,18]). the "0" > will by discarded. > > However, it seems that there isnot any standard function to do it. > > > Sincerely! > > ----- > e^(π.i) + 1 = 0 > -- > View this message in context: > http://haskell.1045720.n5.nabble.com/Can-i-split-a-String-by-its-element-tp3395066p3395066.html > Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com. > > _______________________________________________ > Haskell-Cafe mailing list > [email protected] > http://www.haskell.org/mailman/listinfo/haskell-cafe > _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
