Prelude Data.List.Split> (splitOn [0] . map read . splitOn ",") "2,15,33,0,8,1,16,18" [[2,15,33],[8,1,16,18]]
-Brent On Tue, Feb 22, 2011 at 12:03:45AM -0700, Luke Palmer wrote: > See the http://hackage.haskell.org/package/split package. You should > be able to do this by splitting the string on comma, and then > splitting the result on 0, plus some plumbing. > > Luke > > On Mon, Feb 21, 2011 at 11:46 PM, z_axis <[email protected]> wrote: > > > > I want to split "2,15,33,0,8,1,16,18" to ([2,15,33],[8,1,16,18]). the "0" > > will by discarded. > > > > However, it seems that there isnot any standard function to do it. > > > > > > Sincerely! > > > > ----- > > e^(π.i) + 1 = 0 > > -- > > View this message in context: > > http://haskell.1045720.n5.nabble.com/Can-i-split-a-String-by-its-element-tp3395066p3395066.html > > Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com. > > > > _______________________________________________ > > Haskell-Cafe mailing list > > [email protected] > > http://www.haskell.org/mailman/listinfo/haskell-cafe > > > > _______________________________________________ > Haskell-Cafe mailing list > [email protected] > http://www.haskell.org/mailman/listinfo/haskell-cafe _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
