"Richard O'Keefe" <o...@cs.otago.ac.nz> writes:

>> Then tell me, why does calculating the length of a (Haskell) 
>> list has O(n) complexity.

> Because it is a rather rare operation and the cost of doing
> this would be far higher than you think.

I suspect that if you store the length non-strictly, it would build up
thunks, causing a stack overflow when evaluated.  If it is strict, it
would make a lot of operations that are O(1) today into O(n) operations.

-k
-- 
If I haven't seen further, it is by standing in the footprints of giants

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