Good question. That must be a matter of taste, because as you say the read will always produce the same result. But it sill is a bit of a strange operation.
-- Lennart On Dec 4, 2007 6:25 AM, Conal Elliott <[EMAIL PROTECTED]> wrote: > Oh. Simple enough. Thanks. > > Another question: why the IO in readIVar :: IVar a -> IO a, instead of > just readIVar :: IVar a -> a? After all, won't readIVar iv yield the same > result (eventually) every time it's called? > > > On Dec 3, 2007 12:29 AM, Lennart Augustsson <[EMAIL PROTECTED]> > wrote: > > > You can make them from MVars. > > > > On Dec 2, 2007 8:03 PM, Conal Elliott <[EMAIL PROTECTED]> wrote: > > > > > what became of (assign-once) IVars? afaict, they were in concurrent > > > haskell and now aren't. > > > > > > _______________________________________________ > > > Haskell mailing list > > > Haskell@haskell.org > > > http://www.haskell.org/mailman/listinfo/haskell > > > > > > > > > > _______________________________________________ > Haskell mailing list > Haskell@haskell.org > http://www.haskell.org/mailman/listinfo/haskell > >
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