Conal Elliott wrote:
Oh. Simple enough. Thanks.
Another question: why the IO in readIVar :: IVar a -> IO a, instead
of just readIVar :: IVar a -> a? After all, won't readIVar iv yield
the same result (eventually) every time it's called?
Because it won't necessarily yield the same result the next time you run
it. This is the same reason the stuff in System.Environment returns
values in IO.
Paul.
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