[shell] deleteall does not work quite as advertised
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Key: HBASE-2003
URL: https://issues.apache.org/jira/browse/HBASE-2003
Project: Hadoop HBase
Issue Type: Bug
Reporter: Andrew Purtell
Priority: Minor
Fix For: 0.20.3, 0.21.0
Attachments: HBASE-2003.patch
In the shell, a delete must match the value's coordinates exactly. By default
the delete command uses the latest timestamp but you can provide on explicitly.
So you have to delete each version independent of the others if there are
multiple versions of a value.
The command 'deleteall' is supposed to clear out a whole row or a whole column
of values:
{noformat}
deleteall Delete all cells in a given row; pass a table name, row, and
optionally
a column and timestamp
{noformat}
but the code won't work as advertised:
{code}
def deleteall(row, column = nil, timestamp = HConstants::LATEST_TIMESTAMP)
now = Time.now
d = Delete.new(row.to_java_bytes, timestamp, nil)
@table.delete(d)
@formatter.header()
@formatter.footer(now)
end
{code}
'column' is ignored.
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