[shell] deleteall does not work quite as advertised ---------------------------------------------------
Key: HBASE-2003 URL: https://issues.apache.org/jira/browse/HBASE-2003 Project: Hadoop HBase Issue Type: Bug Reporter: Andrew Purtell Priority: Minor Fix For: 0.20.3, 0.21.0 Attachments: HBASE-2003.patch In the shell, a delete must match the value's coordinates exactly. By default the delete command uses the latest timestamp but you can provide on explicitly. So you have to delete each version independent of the others if there are multiple versions of a value. The command 'deleteall' is supposed to clear out a whole row or a whole column of values: {noformat} deleteall Delete all cells in a given row; pass a table name, row, and optionally a column and timestamp {noformat} but the code won't work as advertised: {code} def deleteall(row, column = nil, timestamp = HConstants::LATEST_TIMESTAMP) now = Time.now d = Delete.new(row.to_java_bytes, timestamp, nil) @table.delete(d) @formatter.header() @formatter.footer(now) end {code} 'column' is ignored. -- This message is automatically generated by JIRA. - You can reply to this email to add a comment to the issue online.