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https://issues.apache.org/jira/browse/HBASE-2003?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
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Andrew Purtell resolved HBASE-2003.
-----------------------------------
Resolution: Fixed
Committed to trunk and 0.20 branch.
> [shell] deleteall ignores column if specified
> ---------------------------------------------
>
> Key: HBASE-2003
> URL: https://issues.apache.org/jira/browse/HBASE-2003
> Project: Hadoop HBase
> Issue Type: Bug
> Reporter: Andrew Purtell
> Assignee: Andrew Purtell
> Priority: Minor
> Fix For: 0.20.3, 0.21.0
>
> Attachments: HBASE-2003.patch
>
>
> In the shell, a delete must match the value's coordinates exactly. By default
> the delete command uses the latest timestamp but you can provide on
> explicitly. So you have to delete each version independent of the others if
> there are multiple versions of a value.
> The command 'deleteall' is supposed to clear out a whole row or a whole
> column of values:
> {noformat}
> deleteall Delete all cells in a given row; pass a table name, row, and
> optionally
> a column and timestamp
> {noformat}
> but the code won't work as advertised:
> {code}
> def deleteall(row, column = nil, timestamp = HConstants::LATEST_TIMESTAMP)
> now = Time.now
> d = Delete.new(row.to_java_bytes, timestamp, nil)
> @table.delete(d)
> @formatter.header()
> @formatter.footer(now)
> end
> {code}
> 'column' is ignored.
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