Thanks Johnny..For note here...
I was doing the same but I did not realized that I was not passing the
values with parameterized strings.
It works.
Here is the snapshot.
ORU_R01 ORU_R01Message = (ORU_R01) theMessage;
for (int i = 0; i<ORU_R01Message.getPATIENT_RESULTReps(); i++) {
for (int j = 0;
j<ORU_R01Message.getPATIENT_RESULT(i).getORDER_OBSERVATIONReps(); j++) {
for (int k = 0;
k<ORU_R01Message.getPATIENT_RESULT(i).getORDER_OBSERVATION(j).getOBSERVA
TIONReps(); k++) {
String terserPath = "/PATIENT_RESULT(" + i +
")/ORDER_OBSERVATION(" + j + ")/OBSERVATION(" + k + ")/OBX-3";
String value= t.get(terserPath);
logger.debug(value);
logger.debug("k=" + k);
}
}
}
-----Original Message-----
From: Johnny2R [mailto:[email protected]]
Sent: Tuesday, August 04, 2009 8:33 AM
To: [email protected]
Subject: Re: [HAPI-devel] How to find Repeating Segments
Sorry, you're right, I was assuming an ORM O01 message (which I've been
burying my head in recently). The same principle applies with an ORU_R01
message, though. Try:
int obxCount =
msg.getPATIENT_RESULT().getORDER_OBSERVATION().getOBSERVATIONReps();
for (int i = 0; i < obxCount; i++) {
OBX obx =
msg.getPATIENT_RESULT().getORDER_OBSERVATION().getOBSERVATION(i).getOBX(
);
//use your terser here
String id = terser.get(obx, 1, 0, 1, 1);
String value = terser.get(obx, 5, 0, 1, 1);
}
Of course, you may have to take account of any repetitions (I'm assuming
one
ORDER_OBSERVATION).
--
View this message in context:
http://www.nabble.com/How-to-find-Repeating-Segments-tp24700999p24809784
.html
Sent from the hl7api-devel mailing list archive at Nabble.com.
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