Hi,
sorry for bothering you. I have found it now in the specification:
http://www.openehealth.org/display/ipf2/Primitive+Type+Constraints
There is this note:
--When primitive type rules are checked--
Note that primitive type rules can only be applied by configuring the parser.
Validation then is executed whenever a primitive value is set:
* during parsing
* when individual fields are modified afterwards, e.g. by while using a
transmogrifier.
Thanks and sorry for interruption. :)
Martin Swiech
----- Original Message -----
From: "Martin Swiech" <mswi...@redhat.com>
To: hl7api-devel@lists.sourceforge.net
Sent: Tuesday, March 31, 2015 1:44:19 PM
Subject: [HAPI-devel] validation while encoding vs. primitive type validation
rules (primitiveRules)
Hi,
I have a question about validating HL7 message with invalid value in primitive
type.
Example:
I am creating HL7 message with invalid telephone number (TN):
private Message createInvalidMessageObj() throws IOException,
HL7Exception {
final ADT_A01 adt = new ADT_A01();
adt.initQuickstart("ADT", "A01", "P");
final MSH mshSegment = adt.getMSH();
mshSegment.getSendingApplication().getNamespaceID().setValue("TestSendingSystem");
mshSegment.getSequenceNumber().setValue("11");
final PID pid = adt.getPID();
pid.getPatientName(0).getFamilyName().getSurname().setValue("Doe");
pid.getPatientName(0).getGivenName().setValue("John");
pid.getPatientIdentifierList(0).getID().setValue("123456");
pid.getPhoneNumberHome(0).get9999999X99999CAnyText().setValue("00420999"); //
phoneNumber should be US telephone number (TN)
return adt;
}
And I will create Parser with DefaultValidation() (default ValidationContext):
final HapiContext hapiContext = new DefaultHapiContext();
hapiContext.setValidationContext(new DefaultValidation());
final Parser parser = hapiContext.getPipeParser();
Parsing of that message will throw an exception and it's OK, because it's not
valid message:
final String invalidMsgStr =
createInvalidMessageObj().toString();
try {
parser.parse(invalidMsgStr);
Assert.fail("DataTypeException expected");
} catch (DataTypeException e) {
Assert.assertTrue(e.getCause() instanceof
ValidationException);
}
But when I am trying to encode that invalid Message object to String (using the
parser with default ValidationContext), no exception is thrown:
try {
parser.encode(createInvalidMessageObj());
Assert.fail("exception expected");
} catch (Exception e) {
//expected
}
Why the primitive rules are not checked when HL7 message is encoded by parser
from Message object to String?
Isn't it bug?
Thanks.
Martin Swiech
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