Hi Jim
How do you create your HttpClient? I once had a similar problem with
trying to log into a server and kept being returned to the login page
- it was solved by reusing the same httpClient for all subsequent
requests of the same user session. (I must admit that I still don't
know exactly why this worked - but it did)
Met Vriendelijke groet/Kind regards,
Ernst Nolte
Email: [email protected]
Website: http://www.synquad.nl
Office: Zwarteweg 6-D, 1412GD, Naarden
Tel: +31(0)35 698 11 55
Fax: +31(0)35 698 27 42
Mob: +31(0)6 813 287 75
On 4 Mar 2010, at 23:13, Langston, James wrote:
Hi Ernst,
After a couple of starts and stops. Yes, using 4.0.1 and
also tried 4.1alpha1 , after doing the post, w/ a username
and password, I do not see the next page, the response shows
just the initial page which has the login/passwords field, but
not the next page which is what I'm expecting to see.
any thoughts ? seems that I'm not posting the login/password.
Jim
HttpPost post = new
HttpPost("http://www.gomeznetworks.com/login.asp";);
List<NameValuePair> vals = new ArrayList<NameValuePair>();
vals.add(new BasicNameValuePair("username", "****"));
vals.add(new BasicNameValuePair("pwd", "****"));
post.setEntity(new UrlEncodedFormEntity(vals, HTTP.UTF_8));
HttpResponse response2 = client.execute(post);
HttpEntity entity2 = response2.getEntity() ;
System.out.println("Login form get: " +
response2.getStatusLine());
System.out.println("Response content length: "
+ entity2.getContentLength());
if (entity2 != null) {
System.out.println(EntityUtils.toString(entity2));
entity2.consumeContent();
}
Jim
/////////////////////////////////////
Jim Langston
Technical Consultant
[email protected]
-----Original Message-----
From: Ernst Nolte [mailto:[email protected]]
Sent: Thursday, March 04, 2010 8:45 AM
To: HttpClient User Discussion
Subject: Re: responding to form login fields
Hi Jim
I assume you use HttpClient v4?
If you look at the form action attribute in the page you will see
this:
<form action="login.asp" method="post" id="form1" name="form1">
So you need to post the parameters to this url:
http://www.gomeznetworks.com/login.asp
and set the fields like this:
HttpPost post = new HttpPost(url);
List<NameValuePair> vals = new ArrayList<NameValuePair>();
vals.add(new BasicNameValuePair("username", "you"));
vals.add(new BasicNameValuePair("pwd", "passwd"));
post.setEntity(new UrlEncodedFormEntity(vals, HTTP.UTF_8));
and now execute it.
as far as the input type image is concerned, I think the onclick event
of image is captured bij Javascript event attachment and in that
handler the form is posted, but I did not bother to verify that.
Met Vriendelijke groet/Kind regards,
Ernst Nolte
Email: [email protected]
Website: http://www.synquad.nl
Office: Zwarteweg 6-D, 1412GD, Naarden
Tel: +31(0)35 698 11 55
Fax: +31(0)35 698 27 42
Mob: +31(0)6 813 287 75
On 4 Mar 2010, at 13:55, Langston, James wrote:
Hi all,
After tons of look up - I haven't been able to find a good example of
being able
to correctly respond to a login form that is using an type="image"
to
initiate the login
process. The fields in the html are:
<td>
Username:<br>
<input
type="text" size="30" maxlength="60" name="username"><br>
Password:<br>
<input
type="password" size="30" maxlength="60" name="pwd">
<input
type="image" src="images/buttons/submit_gray.gif
<view-source:http://www.gomeznetworks.com/images/buttons/submit_gray.gif
" name="login" align="absmiddle">
<input
type="hidden" name="server_string" value="">
<input
type="hidden" name="url_string" value="">
<input
type="hidden" name="query_string" value="">
<input
type="hidden" name="form_string" value="">
</td>
and I need to respond to username, password and login. I do not
understand how to create the NameValuePair to respond to the
image in order to submit the login and move to the next page in the
sequence.
Any thoughts, hints ?
Thanks,
Jim
//////////////////////////////////////////
Jim Langston
Technical Consultant
[email protected]
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