Hi Ernst,
Ok - digging at this a little more, it looks like this is the string
needed for
submitting.
file:///home/jim/Desktop/login.asp?username=****&pwd=****&login.x=&login
.y=&server_string=&url_string=&query_string=&form_string=
I have change my code to reflect those parameters:
List<NameValuePair> vals = new ArrayList<NameValuePair>();
vals.add(new BasicNameValuePair("username", "****"));
vals.add(new BasicNameValuePair("pwd", "****"));
vals.add(new BasicNameValuePair("login.x", ""));
vals.add(new BasicNameValuePair("login.y", ""));
vals.add(new BasicNameValuePair("server_string", ""));
vals.add(new BasicNameValuePair("url_string", ""));
vals.add(new BasicNameValuePair("query_string", ""));
vals.add(new BasicNameValuePair("form_string", ""));
but, the results are the same, any thoughts ?
Jim
////////////////////////////////////
Jim Langston
Technical Consultant
[email protected]
-----Original Message-----
From: Ernst Nolte [mailto:[email protected]]
Sent: Thursday, March 04, 2010 6:01 PM
To: HttpClient User Discussion
Subject: Re: responding to form login fields
On 4 Mar 2010, at 23:57, Oleg Kalnichevski wrote:
> Ernst Nolte wrote:
>> Hi Jim
>> How do you create your HttpClient? I once had a similar problem
>> with trying to log into a server and kept being returned to the
>> login page - it was solved by reusing the same httpClient for all
>> subsequent requests of the same user session. (I must admit that I
>> still don't know exactly why this worked - but it did)
>
> Because along with the HttpClient instance you also kept all cookies
> stored in the cookie store associated with that instance.
That was what I thought so I set all cookies manually, but with no
success - I assume I did not do it correctly.
>
> Oleg
>
>
>> Met Vriendelijke groet/Kind regards,
>> Ernst Nolte
>> Email: [email protected]
>> Website: http://www.synquad.nl
>> Office: Zwarteweg 6-D, 1412GD, Naarden
>> Tel: +31(0)35 698 11 55
>> Fax: +31(0)35 698 27 42
>> Mob: +31(0)6 813 287 75
>> On 4 Mar 2010, at 23:13, Langston, James wrote:
>>> Hi Ernst,
>>>
>>> After a couple of starts and stops. Yes, using 4.0.1 and
>>> also tried 4.1alpha1 , after doing the post, w/ a username
>>> and password, I do not see the next page, the response shows
>>> just the initial page which has the login/passwords field, but
>>> not the next page which is what I'm expecting to see.
>>>
>>> any thoughts ? seems that I'm not posting the login/password.
>>>
>>> Jim
>>>
>>>
>>>
>>> HttpPost post = new
>>> HttpPost("http://www.gomeznetworks.com/login.asp";);
>>>
>>> List<NameValuePair> vals = new ArrayList<NameValuePair>();
>>> vals.add(new BasicNameValuePair("username", "****"));
>>> vals.add(new BasicNameValuePair("pwd", "****"));
>>>
>>> post.setEntity(new UrlEncodedFormEntity(vals, HTTP.UTF_8));
>>>
>>> HttpResponse response2 = client.execute(post);
>>> HttpEntity entity2 = response2.getEntity() ;
>>>
>>> System.out.println("Login form get: " +
>>> response2.getStatusLine());
>>> System.out.println("Response content length: "
>>> + entity2.getContentLength());
>>>
>>> if (entity2 != null) {
>>> System.out.println(EntityUtils.toString(entity2));
>>> entity2.consumeContent();
>>> }
>>>
>>>
>>> Jim
>>>
>>> /////////////////////////////////////
>>>
>>>
>>> Jim Langston
>>> Technical Consultant
>>> [email protected]
>>>
>>>
>>> -----Original Message-----
>>> From: Ernst Nolte [mailto:[email protected]]
>>> Sent: Thursday, March 04, 2010 8:45 AM
>>> To: HttpClient User Discussion
>>> Subject: Re: responding to form login fields
>>>
>>> Hi Jim
>>>
>>> I assume you use HttpClient v4?
>>>
>>> If you look at the form action attribute in the page you will see
>>> this:
>>>
>>> <form action="login.asp" method="post" id="form1" name="form1">
>>>
>>> So you need to post the parameters to this url:
>>>
>>> http://www.gomeznetworks.com/login.asp
>>> and set the fields like this:
>>> HttpPost post = new HttpPost(url);
>>> List<NameValuePair> vals = new ArrayList<NameValuePair>();
>>> vals.add(new BasicNameValuePair("username", "you"));
>>> vals.add(new BasicNameValuePair("pwd", "passwd"));
>>> post.setEntity(new UrlEncodedFormEntity(vals, HTTP.UTF_8));
>>> and now execute it.
>>>
>>> as far as the input type image is concerned, I think the onclick
>>> event
>>> of image is captured bij Javascript event attachment and in that
>>> handler the form is posted, but I did not bother to verify that.
>>>
>>> Met Vriendelijke groet/Kind regards,
>>>
>>> Ernst Nolte
>>>
>>> Email: [email protected]
>>> Website: http://www.synquad.nl
>>> Office: Zwarteweg 6-D, 1412GD, Naarden
>>> Tel: +31(0)35 698 11 55
>>> Fax: +31(0)35 698 27 42
>>> Mob: +31(0)6 813 287 75
>>>
>>> On 4 Mar 2010, at 13:55, Langston, James wrote:
>>>
>>>> Hi all,
>>>>
>>>> After tons of look up - I haven't been able to find a good
>>>> example of
>>>> being able
>>>> to correctly respond to a login form that is using an
>>>> type="image" to
>>>> initiate the login
>>>> process. The fields in the html are:
>>>>
>>>> <td>
>>>> Username:<br>
>>>> <input
>>>> type="text" size="30" maxlength="60" name="username"><br>
>>>> Password:<br>
>>>> <input
>>>> type="password" size="30" maxlength="60" name="pwd">
>>>> <input
>>>> type="image" src="images/buttons/submit_gray.gif
>>>>
>>>
<view-source:http://www.gomeznetworks.com/images/buttons/submit_gray.gif
>>>>> " name="login" align="absmiddle">
>>>>
>>>> <input
>>>> type="hidden" name="server_string" value="">
>>>> <input
>>>> type="hidden" name="url_string" value="">
>>>> <input
>>>> type="hidden" name="query_string" value="">
>>>> <input
>>>> type="hidden" name="form_string" value="">
>>>> </td>
>>>>
>>>> and I need to respond to username, password and login. I do not
>>>> understand how to create the NameValuePair to respond to the
>>>> image in order to submit the login and move to the next page in the
>>>> sequence.
>>>>
>>>> Any thoughts, hints ?
>>>>
>>>> Thanks,
>>>>
>>>> Jim
>>>>
>>>> //////////////////////////////////////////
>>>>
>>>>
>>>>
>>>> Jim Langston
>>>> Technical Consultant
>>>> [email protected]
>>>>
>>>> The contents of this e-mail are intended for the named addressee
>>>> only. It contains information that may be confidential. Unless you
>>>> are the named addressee or an authorized designee, you may not copy
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>>>> error please notify us immediately and then destroy it.
>>>>
>>>
>>>
>>>
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