In a message dated 7/14/2005 1:25:32 A.M. Central Daylight Time, [EMAIL PROTECTED] writes:
IIRC, DS 0H will fill with zeros just as will DC 0H. Why is the latter preferable? DS 'any operand' will not fill the reserved space with anything. The 0H in this case functions only to align to a half word boundary. DC 'any operand' will fill with X'00' bytes any space that is skipped over in order to provide the requested alignment, then generate the requested constant. But if the 'any operand' has a multiplier of 0, then no filling code of X'00' bytes is generated. In this case the 0H functions the same as if the DC were a DS, namely you get aligned to a half word boundary. Bill Fairchild ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECTED] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
