Steve's idea makes sense. I have been using " MAP VTOC(0,7,8) INDEX(0,1,6)", which occupies the rest of cyl 0 and then allocate the HASPACE as 3338 cyls. Either way, maximize your space by minimizing the VTOC.
David Mueller | Systems Programmer | DMS/EITS Phone: 850-414-9134 (Rm 107 SRC) | Fax: 850-921-8343 E-mail: [EMAIL PROTECTED] -----Original Message----- From: IBM Mainframe Discussion List [mailto:[EMAIL PROTECTED] On Behalf Of Thompson, Steve (SCI TW) Sent: Tuesday, September 12, 2006 12:15 PM To: [email protected] Subject: Re: Question : VTOC size - JES2 Volume -----Original Message----- From: IBM Mainframe Discussion List [mailto:[EMAIL PROTECTED] On Behalf Of willie bunter Sent: Tuesday, September 12, 2006 11:11 AM To: [email protected] Subject: Question : VTOC size - JES2 Volume Can anybody please correct me if I am wrong. I have to init a volume for JES2 HASPACE. The volume is a 3390 -3 . Below are my parms for the VTOC. VTOC(0,1,29) INDEX(2,0,45) Is that okay? <snip> I would make the VTOC 1 track with NO index. The only file on the volume will be the HASPACE, right? So a minimal VTOC is all that is needed. Later, Steve Thompson ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECTED] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECTED] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
