In a message dated 7/24/2007 11:14:10 A.M. Central Daylight Time, [EMAIL PROTECTED] writes: >Because the fetch and the store are separated in time. Another CPU or an I/O operation can store into the byte *after* your CPU fetches the byte but *before* your CPU stores the byte. The other CPU update will be wiped out by your CPU subsequent store into the byte. Very clear. Thanks for the enlightenment. Bill Fairchild Plainfield, IL
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