> -----Original Message-----
> From: IBM Mainframe Discussion List On Behalf Of Wayne Driscoll
> 
> Except that an UNPK would leave the field 0C, not C0, so this sounds
> like an old programmers tale to me.

No, UNPK "swaps" the nybbles of the rightmost byte.  P'0' = X'0C'; UNPK
makes it X'C0'.

    -jc-

----------------------------------------------------------------------
For IBM-MAIN subscribe / signoff / archive access instructions,
send email to [email protected] with the message: GET IBM-MAIN INFO
Search the archives at http://bama.ua.edu/archives/ibm-main.html

Reply via email to