For any integer divisor D > 1 and integer dividend d one classical definition of ceil is ceil(d/D) = (d + D - 1)/D Thus ceil(25/2) = (25 + 2 - 1)/2 = 13 ceil(12/6) = (12 + 6 - 1)/6 = 2 ceil(2009/4) = (2009 + 4 - 1)/4 = 503 etc., etc. There is nothing quaint or ad hoc about John McKown's scheme. John Gilmore Ashland, MA 01721-1817 USA
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