This has all been very entertaining but there are two reasons why it is 32760: 1) the storage layout has always consisted of two fullword fields followed by the parameter string storage. The two fullwords plus 32760 bytes of parameters conveniently fits in 8 pages, and 2) 32760 is also the maximum blocksize that the code handles.
W. Kevin Kelley - IBM POK Lab - z/OS Core Development ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
