John,
This is the first time I have had to take exception to a fact that you said and
that is on the comment that we need a 8i multiple.
Even with 64-bit addressing, it doesn't change the length of a branch or jump,
they are still 4 bytes. A jump long is 6 bytes, so maybe 6i is possible, but
that is a weird number to deal with in a binary environment.
Of course you could use 8i with the following
B *+4(R15)
JLU COND0
NOPR 0 never executed, just here to fill space
JLU COND8
NOPR 0
JLU COND16
NOPR 0
...
I think I will continue to prefer the more traditional 4i solution.
Chris Blaicher
Principal Software Engineer, Software Development
Syncsort Incorporated
50 Tice Boulevard, Woodcliff Lake, NJ 07677
P: 201-930-8260 | M: 512-627-3803
E: cblaic...@syncsort.com
-----Original Message-----
From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU] On Behalf
Of John Gilmore
Sent: Wednesday, May 08, 2013 2:39 PM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: Return codes
There are also situations in which one wants to be able to set more than one of
the diagnostic bits in a return code additively and unambiguously, and the
alternative use of 0, 2, 4, 8, 16, . . . , i.e., the sequence 2^i, i = 0, 1,
2, . . . , powers of 2, permits this to be done.
Still, the fact that successive branch-table addresses always differed by four
bytes in probably explains the 4i, i = 0, 1, 2, . . .
convention best.
Now, of course, we need 8i, i= 0, 1, . . . , i.e., 0, 8, 16, 24, . . .
John Gilmore, Ashland, MA 01721 - USA
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