I am not sure I understand Paul Gilmartin's last post. XL6 specifies a target, assembled length of six bytes. There are 6 x 8 = 48 bits available in these 6 bytes.
A 24-hour day contains 60 x 60 x 24 x 1,000,000 = 29,664,400,000,000 µsec 2^48 - 1 = 281,474,976,710,655 These six bytes are thus entirely adequate to contain any unsigned elapsed-µsec value in a 24-hour day. John Gilmore, Ashland, MA 01721 - USA ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
