Per the new PoOps:
LZRG R1,D2(X2,B2) [RXY-a]
The second operand, with the rightmost byte set to zero, is placed
at the first-operand location. [snip] for LZRG, the first and second
operands are 64 bits.
I guess my imagination fails me, so I have to ask... Why?
Dave Cole
ColeSoft Marketing
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