Easy alignment to a 256 byte boundary?

On Tue, 10 Mar 2015 18:57:53 -0400 David Cole <dbc...@colesoft.com> wrote:

:>Per the new PoOps:
:>
:>
:>>LZRG R1,D2(X2,B2) [RXY-a]
:>>
:>>The second operand, with the rightmost byte set to zero, is placed 
:>>at the first-operand location. [snip] for LZRG, the first and second 
:>>operands are 64 bits.
:>
:>
:>I guess my imagination fails me, so I have to ask... Why?

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