On Tue, 9 May 2017 10:42:48 +0300, venkat kulkarni wrote: >Yes. It's not.so I should code jesmsglg dd stmt as >//JESMSGLG dd sysout=a,free=close,spin=unalloc
No, you should not. Doing so would define a DD statement for your step. But the JESYSMSG for the job has already been allocated before your step starts. Look up JESLOG=SPIN. -- Tom Marchant ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [email protected] with the message: INFO IBM-MAIN
