I believe the answer is 22 or 23

Determine the odds of 2 people NOT having the same birthday - then 3 then 4 .. 
keep going until the percentage drops below 50

Chris Hoelscher
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-----Original Message-----
From: IBM Mainframe Discussion List [mailto:[email protected]] On Behalf 
Of Jesse 1 Robinson
Sent: Tuesday, June 20, 2017 3:31 PM
To: [email protected]
Subject: Re: [IBM-MAIN] Store Clock Fast really can give duplicates

(Must be Friday somewhere.) I first heard this ages ago as a puzzle. If you 
want to bet money on matching birthdays in a group of people, how many people 
would you need to give yourself winning odds? Of course, way fewer than most 
people would guess. So you take your winnings and hit the road before they 
figure it out. 

.
.
J.O.Skip Robinson
Southern California Edison Company
Electric Dragon Team Paddler 
SHARE MVS Program Co-Manager
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626-543-6132 Office ⇐=== NEW
[email protected]


-----Original Message-----
From: IBM Mainframe Discussion List [mailto:[email protected]] On Behalf 
Of Paul Gilmartin
Sent: Tuesday, June 20, 2017 11:51 AM
To: [email protected]
Subject: (External):Re: Store Clock Fast really can give duplicates

On Tue, 20 Jun 2017 14:27:33 -0400, Tony Harminc  wrote:

>There's a recent CICS APAR PI82188 that showed up in my Red Alert ...
>
>STCKF and friends have been discussed here and/or the assembler list in 
>recent years, but I've always thought of STCKF clashes as a theoretical 
>problem not likely to be encountered in one's lifetime.
>The APAR description suggests, without clearly saying so, that this has 
>happened at multiple customer sites.
>
>If you're one in a million, and you live in a city of three million people...
> 
It may be far worse than that:  https://en.wikipedia.org/wiki/Birthday_problem

-- gil


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