Sure,
You can have 107, 108 and 103 as the controller
or you could have done:
OSA 0100 ATTACHED TO TCPIP 0100
OSA 0101 ATTACHED TO TCPIP 0101
OSA 0102 ATTACHED TO TCPIP 0102
OSA 0103 ATTACHED TO BH3A 0101
OSA 0104 ATTACHED TO BH3A 0100
OSA 0103 ATTACHED TO BH3A 0102
-----Original Message-----
From: The IBM z/VM Operating System
[mailto:[EMAIL PROTECTED] On Behalf Of Daniel Allen
Sent: Wednesday, September 26, 2007 1:18 PM
To: [email protected]
Subject: OSA question
I have the following OSA environment:
q 100-10f
OSA 0100 ATTACHED TO TCPIP 0100
OSA 0101 ATTACHED TO TCPIP 0101
OSA 0102 ATTACHED TO TCPIP 0102
OSA 0103 FREE
OSA 0104 ATTACHED TO BH3A 0104
OSA 0105 ATTACHED TO BH3A 0105
OSA 0106 ATTACHED TO BH3A 0106
OSA 0107 FREE , OSA 0108 FREE , OSA 0109 FREE , OSA
010A FREE
OSA 010B FREE , OSA 010C FREE , OSA 010D FREE , OSA
010E FREE
OSA 010F FREE
TCPIP requires three addresses and the first two addresses must
be an even-odd pair.
Is that correct ?
If it is correct and I need to add another z/OS guest, I would
use 108, 109 and 10A.
Is there any way to 103 and 107 so all the OSA addresses are
used ?
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