Sure,
 
You can have 107, 108 and 103 as the controller
 
or you could have done:
 
OSA  0100 ATTACHED TO TCPIP    0100

OSA  0101 ATTACHED TO TCPIP    0101

OSA  0102 ATTACHED TO TCPIP    0102                  
 
OSA  0103 ATTACHED TO BH3A     0101

OSA  0104 ATTACHED TO BH3A     0100

OSA  0103 ATTACHED TO BH3A     0102
 
                              
 

        -----Original Message-----
        From: The IBM z/VM Operating System
[mailto:[EMAIL PROTECTED] On Behalf Of Daniel Allen
        Sent: Wednesday, September 26, 2007 1:18 PM
        To: [email protected]
        Subject: OSA question
        
        
        I have the following OSA environment:
         
        q 100-10f

        OSA  0100 ATTACHED TO TCPIP    0100

        OSA  0101 ATTACHED TO TCPIP    0101

        OSA  0102 ATTACHED TO TCPIP    0102

        OSA  0103 FREE

        OSA  0104 ATTACHED TO BH3A     0104

        OSA  0105 ATTACHED TO BH3A     0105

        OSA  0106 ATTACHED TO BH3A     0106

        OSA  0107 FREE    , OSA  0108 FREE    , OSA  0109 FREE    , OSA
010A FREE 
        OSA  010B FREE    , OSA  010C FREE    , OSA  010D FREE    , OSA
010E FREE 
        OSA  010F FREE

         
        TCPIP requires three addresses and the first two addresses must
be an even-odd pair. 
         
        Is that correct ?
         
        If it is correct and I need to add another z/OS guest, I would
use 108, 109 and 10A. 
         
        Is there any way to 103 and 107 so all the OSA addresses are
used ?
         

        
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