Yes, I followed up with my IBM DS8100 support folks and it just so happens that with the DS8100 when you ask for a MOD27 it says to calculate as 3x a MOD9(10017 = 30051). But yes any number of cylinders up to the max of 32,760 would be fine assuming a MOD27. Call it what you want.
Thank You, Terry Martin Lockheed Martin - Citic z/OS and z/VM Performance Tuning and Operating Systems Support Office - 443 348-2102 Cell - 443 632-4191 From: The IBM z/VM Operating System [mailto:[email protected]] On Behalf Of Scott Rohling Sent: Wednesday, February 10, 2010 4:33 PM To: [email protected] Subject: Re: Number of MOD-27 Cylinders for a z/Linux guest I think this whole post got confused :-) No one said a 3390-27 is 30051 cylinders. I said that I would consider making one 30049 cylinders since that equates to 3 3390-9 plus cylinder 0 for a volume label. (3x10016 + 1) A supposed 'standard' 3390-27 is 32760 cyls -- but past 3390-9 -- it's really arbitrary and can be 'whatever you like'... Scott On Wed, Feb 10, 2010 at 1:48 PM, Rob van der Heij <[email protected]> wrote: On Wed, Feb 10, 2010 at 6:38 PM, zMan <[email protected]> wrote: > Right, my guess is that someone said "27 = 3 x 9 = 3 x 10016 = 30048". Then > they added one for cyl0, then they got confused about origin 0/origin 1 and > wound up at 30050. Who's confused? A 3390-3 at 3339 cylinders, one for CP and an almost full pack mini disk is 3338 cylinders. So 3390-27 is 30051 cylinders. If you give the guest a pseudo full pack, that's minus one for CP, so 30050 Rob
