I'm sorry for my sugestions because it's true fgets reads frm file to
first \n char, but i have problem with this line endings and i'll use
this function witchout chop(). I don't know where is the problem and it
is my first problem like that (i'm php programer for few years).
Sorry for my English ...
Marcin
Ryo Chijiiwa napisał(a):
Since fgets reads up to the first new line or the maximum length
specified (i.e. 5000), if the original line lengths are 76 bytes, the
resulting lines will still be 76 bytes.
Ryo
On 1/19/2006, "Marcin Rozmarynowski" <[EMAIL PROTECTED]> wrote:
I think that 5000 bytes is too much to do 76 chars per line after coding
.... but You are a chief :)
it was only sugestion but it works fine.
I think the correct line should be:
$line = chop(fgets($ul_fp,5000))."\r\n";
This way the line endings will be "\r\n" regardless of what it is
$ul_fp.
Ryo
On 1/12/2006, "Andrew Alderwick" <[EMAIL PROTECTED]> wrote:
On 12/1/2006, "Andrew Alderwick" <[EMAIL PROTECTED]> wrote:
On 12/1/2006, "spike2k" <[EMAIL PROTECTED]> wrote:
I have a solution for problem with attachments;
in file include/compose_package.inc i line
//straight transfer if already encoded
while(!eof($ul_fp)){
=>>> $line = chop(fgets($ul_fp,5000));
change to $line = fgets($ul_fp,5000);
without chop(), because this instruction delete whitespaces from string
(including \n charakter which trims base64 coded attachment into 76 chars per
line)
Excellent find. I've also noticed that if the file pointed by $ul_fp is
over 5000 bytes, the beginning of the file would be discarded. Unless
I'm missing something,
$line .= fgets($ul_fp, 5000);
would be even better.
No, it wouldn't. Ignore me! I've just looked at the source - $line is
dealt with before the loop begins again.
If we're chopping out the "chop", do we need to echo \r\n in the
next statement, I wonder?
Andy
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