Hi Mohamed, to avoid making me feel like a commodity, please keep the list in Cc:. This helps other people having the same question, and myself not having to answer the same question multiple times. It also keeps an open communication, a crucial part of what science is all about.
On Tue, 25 Jun 2013, Mohamed Tleis wrote: > On 06/24/2013 05:22 PM, Johannes Schindelin wrote: > > > > On Mon, 24 Jun 2013, Mohamed Tleis wrote: > > > > > ImageJ ij = new ImageJ.Main.launch(); > > As I said, this is not the correct way to launch ImageJ. > > > > First of all, ImageJ.Main.launch is not a class, therefore you cannot > > instantiate it with "new". Second, the correct call to obtain an > > ImageJ context is: > > > > final ImageJ ij = new ImageJ(); > > > > Please have a look at the examples Curtis put so much TLC and effort > > into: > > > > https://github.com/imagej/imagej-tutorials/ > > Thank you Johannes for you reply, > > Although calling new ImageJ() loads the services, it don't show the > interface. That is correct. You have to ask the UIService to show the user interface. Otherwise, truly headless operation would be impossible! And that was an express goal of ImageJ2: to be modular enough so as to make it as useful as possible. > From the tutorial GradientImage.java, the launch method was used. In my > application I want to load the interface with full functionality at a > certain point. Is there any class that shows the interface after > creating ImgeJ ij = new ImageJ(); ? > > /** Tests our command. (GradientImage.java : imageJ-tutorials*/ > public static void main(final String... args) throws Exception { > // Launch ImageJ as usual. > final ImageJ ij = imagej.Main.launch(args); > > // Launch the "Gradient Image" command right away. > ij.command().run(GradientImage.class); > } As I said, ij.ui().showUI() should do it. Ciao, Johannes _______________________________________________ ImageJ-devel mailing list ImageJ-devel@imagej.net http://imagej.net/mailman/listinfo/imagej-devel
