Hi Thiago, On 4/8/12 5:16 AM, Thiago Macieira wrote: >> QVariant result = ...; // Just received from thread >> QMetaMethod method = ...; // Pass the result to this method >> method.invoke(receiver, QGenericArgument(result.typeName(), >> result.value<void *>())); > > You're not supposed to use QGenericArgument directly. Use Q_ARG.
Thanks for your clarifications. Is there a way to achieve the desired behavior with Q_ARG? The main point is that I don't know the actual type of the result, but the QVariant does (although not via templates, apparently). Regards, Jonas
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