On domingo, 8 de abril de 2012 13.00.28, Jonas Gehring wrote: > Hi Thiago, > > On 4/8/12 5:16 AM, Thiago Macieira wrote: > >> QVariant result = ...; // Just received from thread > >> QMetaMethod method = ...; // Pass the result to this method > >> method.invoke(receiver, QGenericArgument(result.typeName(), > >> > >> result.value<void *>())); > > > > You're not supposed to use QGenericArgument directly. Use Q_ARG. > > Thanks for your clarifications. Is there a way to achieve the desired > behavior with Q_ARG? The main point is that I don't know the actual type > of the result, but the QVariant does (although not via templates, > apparently).
Then take a look at what Q_ARG does and replicate it for your code. It does
not involve value<void *>().
--
Thiago Macieira - thiago.macieira (AT) intel.com
Software Architect - Intel Open Source Technology Center
Intel Sweden AB - Registration Number: 556189-6027
Knarrarnäsgatan 15, 164 40 Kista, Stockholm, Sweden
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