> The problem is that QVariant doesn't know how to call it.

Is there a reason why calling qRegisterStreamOperators<QImage>() would't
work ?




-------
Jean-Michaël Celerier
http://www.jcelerier.name

On Wed, May 16, 2018 at 11:52 PM, Thiago Macieira <thiago.macie...@intel.com
> wrote:

> On Wednesday, 16 May 2018 14:38:08 PDT Jérôme Godbout wrote:
> > You will need to provide your own
> >
> > QDataStream& operator<<(QDataStream& ds, const QImage& img)
>
> That's not needed (and won't compile). It already exists.
>
> The problem is that QVariant doesn't know how to call it. So when you have
> a
> QImage inside a QVariant and you try to serialise that QVariant, you get
> nothing useful.
>
> --
> Thiago Macieira - thiago.macieira (AT) intel.com
>   Software Architect - Intel Open Source Technology Center
>
>
>
> _______________________________________________
> Interest mailing list
> Interest@qt-project.org
> http://lists.qt-project.org/mailman/listinfo/interest
>
_______________________________________________
Interest mailing list
Interest@qt-project.org
http://lists.qt-project.org/mailman/listinfo/interest

Reply via email to