> The problem is that QVariant doesn't know how to call it. Is there a reason why calling qRegisterStreamOperators<QImage>() would't work ?
------- Jean-Michaël Celerier http://www.jcelerier.name On Wed, May 16, 2018 at 11:52 PM, Thiago Macieira <thiago.macie...@intel.com > wrote: > On Wednesday, 16 May 2018 14:38:08 PDT Jérôme Godbout wrote: > > You will need to provide your own > > > > QDataStream& operator<<(QDataStream& ds, const QImage& img) > > That's not needed (and won't compile). It already exists. > > The problem is that QVariant doesn't know how to call it. So when you have > a > QImage inside a QVariant and you try to serialise that QVariant, you get > nothing useful. > > -- > Thiago Macieira - thiago.macieira (AT) intel.com > Software Architect - Intel Open Source Technology Center > > > > _______________________________________________ > Interest mailing list > Interest@qt-project.org > http://lists.qt-project.org/mailman/listinfo/interest >
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