On 26 October 2010 15:48, Daniel Convissor <dani...@analysisandsolutions.com> wrote: > On Mon, Oct 25, 2010 at 12:56:28AM +0200, Etienne Kneuss wrote: > >> Exactly, if Bar::getFoo is not called statically, parent::getFoo() will >> not be a static call, it should not get through __callStatic. > > That logic sounds good. Unfortunately, things aren't behaving that way: > > <?php > > // Rework of code from http://bugs.php.net/bug.php?id=51176 > class p { > public function __call($n, $a) { > echo "call\n"; > } > > public static function __callStatic($n, $a) { > echo "callStatic\n"; > } > } > > class c extends p { > public function existing() { > parent::non_existing(); > } > } > > $c = new c; > echo 'static = '; > c::s(); > echo 'object = '; > $c->o(); > echo 'parent = '; > $c->existing(); > > echo phpversion() . "\n"; > > > Thanks, > > --Dan
So the calling context/scope is going to have to be used to determine if the call should get to __call or __callStatic. Is that possible? Appropriate? Easy to do? Done by Friday? -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php
