Hi, Martin T je dne 21/08/14 14:17 napisal-a:
How did Iperf calculate, that it sent 71.5 MBytes? I mean it says it has sent 51021 datagrams and one datagram is 1470B so I should have sent 75MB instead(51021*1470/10^6).
Formula 151021*1470/1024/1024 gives 71.5264 as result. Probably the printout should rather read [ 4] 0.0-60.0 sec 71.5 MiBytes 10.0 Mbits/sec(note the 'i' in MiBytes). The (unwritten) consent in IT seems to be that the data rates (specially so at serial data transmission) should be in decimal prefixes (M = 10^6) while data volumes should be in binary prefixes (M = 2^10) ... at least in technical departments, marketing departments seem to strictly use decimal prefixes as they give slightly larger numbers.
-- Peace! Mkx -- perl -e 'print $i=pack(c5,(41*2),sqrt(7056),(unpack(c,H)-2),oct(115),10);' -- echo 16i[q]sa[ln0=aln100%Pln100/snlbx]sbA0D4D465452snlb xq | dc ------------------------------------------------------------------------------ BOFH excuse #47: Complete Transient Lockout
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