> Depends on what level of "collision risk" you are happy with, and this > depends on the scenario where you are assessing that risk. > > [...] > > - a set of us pick numbers from a pool, and we compare numbers. The > probability that two or us have picked the same number is the case where > a random draw function exceeds 0.5 after 1.24 million random draws. > The general solution of the probability of a collision after d draws > from n possible values is given by: > > P = 1 - ((n!) / ((n**d)((n-d)!))) > > Given that the value for n here is 2.199,023,255,552, then the objective > is to find the lowest value of d for which P is greater than or equal > to 0.5. In this case the value for d is some 1.24 million. > > i.e. if we all pick numbers and stuff them into the DNS, then by the > time the 1,240,000 selection had taken place the probability that a > collision has occurred exceeds 0.5
It's not a collision until two of those systems connect together. -- George Mitchell > regards, > > Geoff -------------------------------------------------------------------- IETF IPv6 working group mailing list [email protected] Administrative Requests: https://www1.ietf.org/mailman/listinfo/ipv6 --------------------------------------------------------------------
