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Hi Martin
It is not the port in the JServ that I was talking about it is the port in
the services file of the Win32 Operating System. At Win95/98 it is normally
c:\windows\services at WinNT it is c:\winNT\system32\drivers\etc\services
This services file is the configuration for the TCP/IP ports and it needs an
entry for the port you use 8007.
Paulo
-----Original Message-----
From: Martin Widmer [mailto:[EMAIL PROTECTED]]
Sent: Terça-feira, 8 de Fevereiro de 2000 12:46
To: Java Apache Users
Subject: RE: JServ Error: "(EMERGENCY) ajp12: can not connect to host
127 .0.0.1:8007" on Wim32 platform
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BEFORE YOU POST, search the faq at <http://java.apache.org/faq/>
WHEN YOU POST, include all relevant version numbers, log files,
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----------------------------------------------------------------
Hi Paolo
At 12:31 08.02.2000 +0000, you wrote:
>Hi!
>
>Did you check if the 8007 port is in the services file?
>
>Paulo
Yes. This is a snippet of my httpd.conf file:
# Default port that Apache JServ is listening to
# Syntax: ApJServDefaultPort [number]
# Default: protocol-dependant (for ajpv12 protocol this is "8007")
ApJServDefaultPort 8007
So there is the port. I checked the .conf file of the servlet zones but it
seems like there is no other entry with the port number for JServ.
Martin
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>Hello !
>
>Due to the FAQ search is down and the new FAQ is down too I am posting
this:
>
>I use JServ 1.1 with JSDK 2.0, JDK 1.2.2 and Apache 1.3.9 on a experimental
>Win95 platform with Winsock upgraded to V. 2. Apache works and also the
>JServ status page is accessible. But when I try to invoke a servlet, I get
>the error message shown in the subject. Can anyone help me ?
>
>Martin
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