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The '& 0xffff' won't place 0's in the higher registers. It will just
leave them there if they're already present. If, on the other hand,
there are 1's there, it'll leave those too...
But, as you said, it doesnt really matter :-)
-MG
Arkaitz Bitorika wrote:
> You are supposing that the Java integers are 16 bit long, and I think they
> actually are 32 bit integers, so the & 0xffff operation will put 0s in
> the higher 16 bits.
> I have no idea what it is doing this here, but it certainly *is* having an
> effect.
>
> Cheers,
>
> Arkaitz.
>
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