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Good point... my mistake

-MG

Fernando Salazar wrote:
> 
> ----------------------------------------------------------------
> BEFORE YOU POST, search the faq at <http://java.apache.org/faq/>
> WHEN YOU POST, include all relevant version numbers, log files,
> and configuration files.  Don't make us guess your problem!!!
> ----------------------------------------------------------------
> 
> Um, since a Java int value of specified by the literal '0xffff' has a 32-bit
> value of 0x0000FFFF, how does a bitwise AND with such a value not
> zero-out the hi-order byte?
> 
> - Fernando
> 
> >
> > The '& 0xffff' won't place 0's in the higher registers. It will just
> > leave them there if they're already present.  If, on the other hand,
> > there are 1's there, it'll leave those too...
> >
> > But, as you said, it doesnt really matter :-)
> >
> > -MG
> >
> > Arkaitz Bitorika wrote:
> > > You are supposing that the Java integers are 16 bit long, and I
> > think they
> > > actually are 32 bit integers, so the & 0xffff operation will put 0s in
> > > the higher 16 bits.
> > > I have no idea what it is doing this here, but it certainly
> > *is* having an
> > > effect.
> > >
> > > Cheers,
> > >
> > > Arkaitz.
> > >
> >
> >
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