I believe that all browsers maintain the *original* source that they
receive. This used to bug the heck out of me until a) the FF
WebDeveloper extension came along with "view rendered source" and, b)
I realised that it's in everyone's best interest that the browser
inform you of the exact nature of the source that was received from
the server. Now, of course, there's also firebug with which to see the
changes.
Whether browsers should include a "view rendered source" option by
default is another matter. (hmmm ... maybe I should go dig around in
about:config)
On Sat, Feb 7, 2009 at 11:48 PM, gberz3 <gbe...@gmail.com> wrote:
>
> Alrighty. First and foremost color me embarrassed, but I wasn't aware
> that the actual source wasn't manipulated. For instance, if I click
> on the browsers' VIEW SOURCE, it maintains the original. However, if
> I view the OBJECT via the CONSOLE of either Firebug, or view the HTML
> via the CONSOLE in Safari then I see the changes.
>
> Is this something I should have picked up in Javascript 101? Do
> browsers always maintain the original source? And more important,
> where would I have found this bit of information? What, exactly, is
> the most efficient workflow for testing items of this nature?
>
> On Feb 7, 11:32 pm, brian <bally.z...@gmail.com> wrote:
>> Do you see the class added in firebug's HTML view?
>>
>> On Sat, Feb 7, 2009 at 10:49 PM, gberz3 <gbe...@gmail.com> wrote:
>>
>> > Ok, this is odd. I can perform a .fadeOut() on the acquired divs, but
>> > the .addClass() method specifically isn't working. Is there anything
>> > in particular that I can check? Specific syntax? Anything?
>>
>> > Also, thanks for the quick support.
>>
>> > On Feb 7, 10:33 pm, "Mauricio \(Maujor\) Samy Silva"
>> > <css.mau...@gmail.com> wrote:
>> >> There is nothing wrong with your jQuery code.
>> >> Double check the link to jQuery library and the HTML markup.
>>
>> >> Try this example tested here:
>>
>> >> <style type="text/css" media="all">
>> >> .midget {background:red}
>> >> </style>
>>
>> >> <script
>> >> src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.1/jquery.min.js";></script>
>>
>> >> <script type="text/javascript">
>> >> $(document).ready(function(){
>> >> $(".testclass").each(function(){
>> >> $(this).addClass("midget");});
>>
>> >> });
>> >> </script>
>> >> ...
>> >> <body>
>> >> <p class="testclass">Some text</p>
>> >> <b class="testclass">Some bold text</b>
>> >> ...
>>
>> >> -----Mensagem Original-----
>> >> De: "gberz3" <gbe...@gmail.com>
>> >> Para: "jQuery (English)" <jquery-en@googlegroups.com>
>> >> Enviada em: domingo, 8 de fevereiro de 2009 01:07
>> >> Assunto: [jQuery] Using selectors successfully...?
>>
>> >> > Will someone please explain to me why the following code fails to
>> >> > execute? I have a simple test page set up and jquery doesn't seem
>> >> > happy with what I'm trying to do. I get no errors, and when I log to
>> >> > console in firebug it shows that it is indeed finding my two objects,
>> >> > however it won't actually perform 'addClass':
>>
>> >> > $(document).ready(function() {
>>
>> >> > $(".testclass").each(function(){
>> >> > $(this).addClass("midget");
>> >> > });
>> >> > });
>>
>> >> > At first I just figured it was because I wasn't doing an "each", but
>> >> > then after trying each and having it still fail, I was back to square
>> >> > one. Also, is it not possible to select based on tags (e.g.
>> >> > 'div.divclass')?
>>
>> >> > Any help would be much appreciated.
>>
>> >> > Best!
