I'm just glad it only took 2 hours, and not 2 weeks. I always tend to
think outside the box. Unfortunately, I often find myself inside
another box just beside the original box. Are there any sorts of
explicit documentation that warns against "gotchas" of this nature?
Thanks for the hand-holding all. You guys rock!
On Feb 8, 12:28 am, brian <bally.z...@gmail.com> wrote:
> I believe that all browsers maintain the *original* source that they
> receive. This used to bug the heck out of me until a) the FF
> WebDeveloper extension came along with "view rendered source" and, b)
> I realised that it's in everyone's best interest that the browser
> inform you of the exact nature of the source that was received from
> the server. Now, of course, there's also firebug with which to see the
> changes.
>
> Whether browsers should include a "view rendered source" option by
> default is another matter. (hmmm ... maybe I should go dig around in
> about:config)
>
> On Sat, Feb 7, 2009 at 11:48 PM, gberz3 <gbe...@gmail.com> wrote:
>
> > Alrighty. First and foremost color me embarrassed, but I wasn't aware
> > that the actual source wasn't manipulated. For instance, if I click
> > on the browsers' VIEW SOURCE, it maintains the original. However, if
> > I view the OBJECT via the CONSOLE of either Firebug, or view the HTML
> > via the CONSOLE in Safari then I see the changes.
>
> > Is this something I should have picked up in Javascript 101? Do
> > browsers always maintain the original source? And more important,
> > where would I have found this bit of information? What, exactly, is
> > the most efficient workflow for testing items of this nature?
>
> > On Feb 7, 11:32 pm, brian <bally.z...@gmail.com> wrote:
> >> Do you see the class added in firebug's HTML view?
>
> >> On Sat, Feb 7, 2009 at 10:49 PM, gberz3 <gbe...@gmail.com> wrote:
>
> >> > Ok, this is odd. I can perform a .fadeOut() on the acquired divs, but
> >> > the .addClass() method specifically isn't working. Is there anything
> >> > in particular that I can check? Specific syntax? Anything?
>
> >> > Also, thanks for the quick support.
>
> >> > On Feb 7, 10:33 pm, "Mauricio \(Maujor\) Samy Silva"
> >> > <css.mau...@gmail.com> wrote:
> >> >> There is nothing wrong with your jQuery code.
> >> >> Double check the link to jQuery library and the HTML markup.
>
> >> >> Try this example tested here:
>
> >> >> <style type="text/css" media="all">
> >> >> .midget {background:red}
> >> >> </style>
>
> >> >> <script
> >> >> src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.1/jquery.min.js";></script>
>
> >> >> <script type="text/javascript">
> >> >> $(document).ready(function(){
> >> >> $(".testclass").each(function(){
> >> >> $(this).addClass("midget");});
>
> >> >> });
> >> >> </script>
> >> >> ...
> >> >> <body>
> >> >> <p class="testclass">Some text</p>
> >> >> <b class="testclass">Some bold text</b>
> >> >> ...
>
> >> >> -----Mensagem Original-----
> >> >> De: "gberz3" <gbe...@gmail.com>
> >> >> Para: "jQuery (English)" <jquery-en@googlegroups.com>
> >> >> Enviada em: domingo, 8 de fevereiro de 2009 01:07
> >> >> Assunto: [jQuery] Using selectors successfully...?
>
> >> >> > Will someone please explain to me why the following code fails to
> >> >> > execute? I have a simple test page set up and jquery doesn't seem
> >> >> > happy with what I'm trying to do. I get no errors, and when I log to
> >> >> > console in firebug it shows that it is indeed finding my two objects,
> >> >> > however it won't actually perform 'addClass':
>
> >> >> > $(document).ready(function() {
>
> >> >> > $(".testclass").each(function(){
> >> >> > $(this).addClass("midget");
> >> >> > });
> >> >> > });
>
> >> >> > At first I just figured it was because I wasn't doing an "each", but
> >> >> > then after trying each and having it still fail, I was back to square
> >> >> > one. Also, is it not possible to select based on tags (e.g.
> >> >> > 'div.divclass')?
>
> >> >> > Any help would be much appreciated.
>
> >> >> > Best!
