Thanks for the reply firstly. :) Since I'm talking about a default jQuery function I didn't give a full example. If you think that I'd help let me give you one.
I have simplified my code for the example, here it goes: http://blockedmind.com/jq/fadeout.html When you click a link, the others are disappearing and a message is added to the testing paragraf. I want to get "Executed" text added once. But it is added as many as the count of siblings due to default options of fadeOut callback function. And no, I can not put it elsewhere because I have more effects after click in my real situation and I need to get that message after all of them completed and for once of course. I hope I am clear? On Apr 19, 4:44 pm, Karl Swedberg <k...@englishrules.com> wrote: > Would you mind giving us some code to look at? Or point us to a test > page? It might be easier to help you if we have something to look at. > > --Karl > > ____________ > Karl Swedbergwww.englishrules.comwww.learningjquery.com > > On Apr 19, 2009, at 7:22 AM, blockedmind wrote: > > > > > Hmmm... > > > On Apr 18, 2:28 am, blockedmind <blockedm...@gmail.com> wrote: > >> Nothing? > > >> On Apr 17, 8:46 pm, blockedmind <blockedm...@gmail.com> wrote: > > >>> This problem occurs when $("#menu li a").fadeOut(function() {}); > >>> being > >>> used. callback function is called 3 times 'cos there is 3 li > >>> elements. > > >>> On Apr 17, 7:28 pm, blockedmind <blockedm...@gmail.com> wrote: > > >>>> Callback function of fadeOut effect is executed once for each > >>>> element > >>>> animated against. Is it possible to make it executed once after all > >>>> elements faded?
