Thanks very much.

On Apr 20, 2:19 am, Karl Swedberg <k...@englishrules.com> wrote:
> You could do something like this:
>
> $(document).ready(function() {
>         $("#menu ul li a").click(function(e) {
>                 e.preventDefault();
>                 var $sibs = $(this).parent().siblings();
>                 $sibs.fadeOut(function() {
>                   if ( $sibs.index(this) == $sibs.length-1 ) {
>                         $("p").append("Executed. ");                
>                   }
>                 });
>         });
>         $("p").append("Page loaded. ");
>
> });
>
> This will only append "Executed." for the last sibling in the group.  
> ($sibs.index(this) == $sibs.length-1).
>
> --Karl
>
> ____________
> Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> On Apr 19, 2009, at 6:01 PM, blockedmind wrote:
>
>
>
> > Thanks for the reply firstly. :) Since I'm talking about a default
> > jQuery function I didn't give a full example. If you think that I'd
> > help let me give you one.
>
> > I have simplified my code for the example, here it goes:
> >http://blockedmind.com/jq/fadeout.html
>
> > When you click a link, the others are disappearing and a message is
> > added to the testing paragraf. I want to get "Executed" text added
> > once. But it is added as many as the count of siblings due to default
> > options of fadeOut callback function.
>
> > And no, I can not put it elsewhere because I have more effects after
> > click in my real situation and I need to get that message after all of
> > them completed and for once of course.
>
> > I hope I am clear?
>
> > On Apr 19, 4:44 pm, Karl Swedberg <k...@englishrules.com> wrote:
> >> Would you mind giving us some code to look at? Or point us to a test
> >> page? It might be easier to help you if we have something to look at.
>
> >> --Karl
>
> >> ____________
> >> Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> >> On Apr 19, 2009, at 7:22 AM, blockedmind wrote:
>
> >>> Hmmm...
>
> >>> On Apr 18, 2:28 am, blockedmind <blockedm...@gmail.com> wrote:
> >>>> Nothing?
>
> >>>> On Apr 17, 8:46 pm, blockedmind <blockedm...@gmail.com> wrote:
>
> >>>>> This problem occurs when $("#menu li a").fadeOut(function() {});
> >>>>> being
> >>>>> used. callback function is called 3 times 'cos there is 3 li
> >>>>> elements.
>
> >>>>> On Apr 17, 7:28 pm, blockedmind <blockedm...@gmail.com> wrote:
>
> >>>>>> Callback function of fadeOut effect is executed once for each
> >>>>>> element
> >>>>>> animated against. Is it possible to make it executed once after  
> >>>>>> all
> >>>>>> elements faded?

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