Sorry, maybe my response was somewhat confusing, but I don't believe
you'll get a concatenated string (as the OP's followup indicates).
After using .filter(), you'll get an array-like object (it's still the
jQuery object) which contains the text nodes.
Calling .text() on those won't actually concatenate them though, as
they're text nodes.
Likewise, if you do $('div').contents().text() you'll only get the
text of the UL element, rather than a concatenation of that with the
previous text node.
@nick, you can get the text from the object with text[0].nodeValue.
HTH :)
On May 3, 4:08 pm, Karl Swedberg <k...@englishrules.com> wrote:
> On May 2, 2009, at 9:28 PM, mkmanning wrote:
>
> > Don't use .text(), you'll get an array-like object of text nodes.
>
> Tiny clarification: you'll get a concatenated string of text nodes.
>
> --Karl
>
> ____________
> Karl Swedbergwww.englishrules.comwww.learningjquery.com
>
> On May 2, 2009, at 9:28 PM, mkmanning wrote:
>
>
>
> > Don't use .text(), you'll get an array-like object of text nodes. Try
>
> > var text = $('div').contents().filter(function(){return
> > this.nodeType==3;});
> > console.log(text)
>
> > On May 2, 6:06 pm, nick <nboutel...@gmail.com> wrote:
> >> Thanks for the response. Are you sure thats correct though?
>
> >> alert($('div').contents().filter(function(){return
> >> this.nodeType==3;}).text());
>
> >> returns empty.
