Sorry, I must have misunderstood the context. I was responding to this:
Don't use .text(), you'll get an array-like object of text nodes
It seemed like you were saying that .text() returns an array-like
object. But if it's used as a getter (without an argument), it returns
a string. If there is more than one element in the jQuery object, it
concatenates the text values. So, given the OP's markup, doing $('div
li').text() would return "SymphilisGhonoreahAids". Anyway, I know you
already know this. Just trying to clarify for others who are newer.
Hope I didn't muddy the water even more.
@nick, Another way to get "Free sex" out of that div is to do this:
$('div')[0].firstChild.nodeValue
That will give you leading and trailing white space, though, so you
can use jQuery's trim function to strip it:
$.trim( $('div')[0].firstChild.nodeValue );
You'll have to adjust the selector, too, if that div isn't the first
one in your document.
--Karl
____________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On May 4, 2009, at 9:29 PM, mkmanning wrote:
Sorry, maybe my response was somewhat confusing, but I don't believe
you'll get a concatenated string (as the OP's followup indicates).
After using .filter(), you'll get an array-like object (it's still the
jQuery object) which contains the text nodes.
Calling .text() on those won't actually concatenate them though, as
they're text nodes.
Likewise, if you do $('div').contents().text() you'll only get the
text of the UL element, rather than a concatenation of that with the
previous text node.
@nick, you can get the text from the object with text[0].nodeValue.
HTH :)
On May 3, 4:08 pm, Karl Swedberg <k...@englishrules.com> wrote:
On May 2, 2009, at 9:28 PM, mkmanning wrote:
Don't use .text(), you'll get an array-like object of text nodes.
Tiny clarification: you'll get a concatenated string of text nodes.
--Karl
____________
Karl Swedbergwww.englishrules.comwww.learningjquery.com
On May 2, 2009, at 9:28 PM, mkmanning wrote:
Don't use .text(), you'll get an array-like object of text nodes.
Try
var text = $('div').contents().filter(function(){return
this.nodeType==3;});
console.log(text)
On May 2, 6:06 pm, nick <nboutel...@gmail.com> wrote:
Thanks for the response. Are you sure thats correct though?
alert($('div').contents().filter(function(){return
this.nodeType==3;}).text());
returns empty.
